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Area of rectangle = length $\times$ breadth

\[Rs.750\] represents the cost of \[1000\] bricks.

\[Rs.49500\] represents cost of ? bricks, which represents the total number of bricks used.

Therefore, the total number of bricks used is given as follows:

$\begin{align}

& \dfrac{Total\text{ }\cos t\text{ }of\text{ }used\text{ }bricks}{\cos t\text{ }of\,1000\text{ }bricks}\times 1000\text{ }bricks \\

& =\dfrac{49500}{750}\times 1000 \\

& =66000 \\

\end{align}$

The total number of bricks used is $66000$.

Area occupied by the total number of bricks represents the area of the lane.

Therefore,

$\begin{align}

& Area\text{ }of\text{ }lane=total\text{ n}umber\text{ }of\text{ }bricks\times area\text{ }of\text{ }each\text{ }brick \\

& \Rightarrow l\times 5m=66000\times (20cm\times 15cm) \\

& \Rightarrow l=\dfrac{66000\times (20cm\times 15cm)}{5m} \\

& \Rightarrow l=\dfrac{66000\times (20cm\times 15cm)}{500cm} \\

& \Rightarrow l=39600cm \\

& \Rightarrow l=396m \\

\end{align}$